Hello all!
How can I get Excel to generate all possible double deck compositions in four-column card totals
Column 1 = aces (total n cards = 0 to 8)
Column 2 = 789 (total n cards = 0 to 24) ...
I am beginner, I have 2 books "Professional Blackjack" and "Blackjack Attack", from those books what chapters should I study the most. It's so much information.
How much unit loss do you have before you raise suspicion of either ou are doing something wrong and or there’s cheating or mistake on dealer part or whatever?
I am currently 80 units down in...
Norm, there are a couple of problems I am experiencing with CVCX V6.0.289. I'm sure other users are encountering similar issues.
First and foremost, every time I run a simulation and select...
A question for math-minded folks...
If the prior probabilities of a given card landing on the first box, second box, third box are 40%, 15%, 10%, respectively,
what is the posterior probabilities...
I am using CVBJ software, with the Hi-Lo. Why is the TC=-1, if there is Remaining Count = 6, Running Count -4, TC -1 when it's the first hand. Should the TC 0 esp. if you this first hand.
So I am new , and just trying to get some info on black jack bots . If there’s ones here reputable I can purchase ? And how I can use or go about using it to win real money online in casinos ? If...
Right now I live in Asia, No double deck games and most bigger joints have only shuffle machines. I am currently playing the spin & go format (poker) at a professional level at PS online. To stay in...
That is great data. I am using the KO system (mostly playing 6D, H17, DAS); IRC = -20.
With that said, would it be too much to ask for you to provide similar data as above, but for the KO system...
Yep, I believe this is the correct approach. Therefore, if the Ace didn't land in the first spot, the probabilities increase for the following spots:
25% (instead of 15%) for the second spot, 16.7%...
Here's how I would look at it.
Successes of card landing on spot 1, spot 2, spot 3, eventually somewhere
success(1) = .4
success(2) = .15
success(3) = .1
success(>3) = .35
if trial 1 fails...
Three boxes, A=40%, B=15%, C=10%.
"The 40% event did not happen", remaining 60%.
In this 60%, 15% is in B, 10% is in C.
Therefore, 15/60 will be in B, 10/60 will be in C, and 35/60 went somewhere...
But he wasn't asking for EVs. He was asking for the probability of a card landing in one of the first three boxes and then the probability after one sees that box 1 isn't successful that it will land...
Here's example to show relationship:
Single deck, S17, SPL1, SPLA1, NDAS
Overall EV best strategy: +.0248%
EV given up card A: -36.03%
EV given up card 2: +9.995%
EV given up card 3: +13.59%...
So, a total of 65%.
Did you mean this? Doesn't make sense. Did you mean to say "of the second and third box when the 40% event did not happen?"? If you did, then you have 65% left for those...
In a normally cutted game, the probability of receiving a single given card will never be as high as 40%.
The probability of receiving a 10,J,Q,K may reach 40% and will go up if the next card is a...
You need to get over this paranoia and also learn what kind of variance is typical and can be expected. A true AP does not even begin to think of such things just for losing 80 units (assuming you...
